Aren't the powers too large?

Algebra Level 3

2 300 , 3 200 \large\color{#D61F06}{2^{300} , 3^{200}}

Find the greater number.

3 200 3^{200} Both 2 300 2^{300}

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3 solutions

Anuj Shikarkhane
Aug 16, 2015

2 300 2^{300} can also be written as ( 2 3 ) 100 (2^3)^{100} .

This is same as 8 100 8^{100} .

3 200 3^{200} can also be written as ( 3 2 ) 100 (3^2)^{100} .

This is same as 9 100 9^{100} .

9 100 > 8 100 9^{100} > 8^{100} .

Therefore 3 200 3^{200} is greater than 2 300 2^{300} .

(Upvote if you are satisfied.)

I am satisfied. Upvoted!

Nelson Mandela - 5 years, 10 months ago

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Thanks! @nelson mandela

Anuj Shikarkhane - 5 years, 10 months ago

Definitely the most simplest solution.Upvoted!

Athiyaman Nallathambi - 5 years, 10 months ago

One of the options is very funny. When you are asking which is greater how can "both" be one of the options?

Kushagra Sahni - 5 years, 10 months ago
Cleres Cupertino
Aug 17, 2015

3 200 = 9 100 > 8 100 = 2 300 3^{200}=9^{100}>8^{100}=2^{300}

Dev Sharma
Aug 16, 2015

2^300 has 91 digits.

3^200 has 96 digits.

Now 3^200 is greater.

You should try and mention how you got the digits but otherwise a good solution.

Athiyaman Nallathambi - 5 years, 10 months ago

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using logarithm, i found the digits

Dev Sharma - 5 years, 10 months ago

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I kind of guessed that.But if you had actually written down the method in your solution it would be much better.

Athiyaman Nallathambi - 5 years, 10 months ago

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