Arithmetic mean

Algebra Level 2

A set of 21 21 numbers has an average of 4 4 . Another set of 100 100 numbers has an average of 5.21 5.21 . Find the average of the numbers in the sets combined.

4.605 5 None of these

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Some of you might say that solution is 4 + 5.21 2 = 4.605 \dfrac{4+5.21}{2}=4.605 . This is wrong.

In the first set, there are 21 21 numbers and the average is 4 4 . That means that the sum of the numbers in the first set is ( 21 ) ( 4 ) = 84 (21)(4)=84 . It follows that the sum of the numbers in the second set is ( 100 ) ( 5.21 ) = 521 (100)(5.21)=521 . The total sum of numbers in the 2 2 sets is 84 + 521 = 605 84+521=605 . The average is total sum divided by the total numbers.

a v e r a g e = 605 21 + 100 = 605 121 = average=\dfrac{605}{21+100}=\dfrac{605}{121}= 5 \boxed{5} a n s w e r \large\color{#D61F06}\boxed{answer}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...