Arithmetic Operation

Algebra Level 4

Let z 1 = a + b i z_1=a+bi and z 2 = c + d i z_2=c+di be complex numbers, where a a , b b , c c and d d are real numbers and a 0 a \neq 0 and c 0 c \neq 0 . An arithmetic operation \ast is defined as follows: z 1 z 2 = a c + ( a d + b c ) i . z_1 \ast z_2 = ac+(ad+bc)i. Let z 3 = 1 2 1 4 i z_3 = \frac{1}{2}-\frac{1}{4}i . If the inverse element of z 3 z_3 for \ast is p + q i p + qi , where p p and q q are real numbers, what is the value of p 2 + q 2 p^2 + q^2 ?

17 10 5 13

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1 solution

Atiq Ahmed
Feb 27, 2014

z1 z2=ac+(ad+bc)i means 1+0i is identity for operation * , so (1/2 -1/4 i) (p +qi) = 1 +0i . Now by definition of operation * 1/2 p = 1 and 1/2 q - 1/4 p = 0. hence p =2 and q = 1/2 p i.e. p=2 and q = 1 therefore p^2+ q^2 = 5

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