Arithmetic Progression

Algebra Level 2

The first term of an arithmetic progression is -8.

Find the sum of the arithmetic progression up to 12 terms if the second term is -4.


The answer is 168.

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1 solution

Tapas Mazumdar
Sep 15, 2016

Given,

a = 8 d = 4 ( 8 ) = 4 a = -8 \\ d = -4-(-8) = 4

So, using S n = n 2 { 2 a + ( n 1 ) d } S_{n} = \dfrac{n}{2}\left\{2a+(n-1)d\right\}

S 12 = 12 2 { 2 ( 8 ) + ( 12 1 ) ( 4 ) } = 6 { 16 + 44 } = 6 × 28 = 168 S_{12}= \dfrac{12}{2}\left\{2(-8)+(12-1)(4)\right\} \\ ~~~~~~ = 6\left\{-16+44\right\} \\ ~~~~~~ = 6\times 28 \\ ~~~~~~ = \boxed{168}

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