Arithmetic Progressions

Algebra Level 1

Find the value of m m in the arithmetic progression with consecutive terms m , 13 , 3 m 6 m,13,3m-6\ldots .


The answer is 8.

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2 solutions

We can do it by taking common difference but I am doing by Arithmetic mean formula.

m , 13 , 3 m 6 , . . . . . \Rightarrow m,13,3m-6,.....

3 m 6 + m 2 = 13 \Rightarrow \dfrac{3m-6+m}{2}=13

4 m = 32 \Rightarrow 4m=32

m = 8 \therefore m=\boxed{8}

We have an arithmetic sequence. So 13 m = d 13-m=d

and 3 m 6 13 = d 3m-6-13=d

Then 13 m = 3 m 19 32 = 4 m m = 8 13-m=3m-19 \Rightarrow 32=4m \Rightarrow m=8

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