Arrange your own restaurant

Algebra Level 2

Supposedly the ratio of the number of the tables to chairs in a restaurant is 4 : 9 4 : 9 . I remove 2 2 tables and 4 4 chairs, and the new ratio is 7 : 16 7 : 16 .

What is the total number of tables and chairs that are left?


The answer is 46.

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1 solution

Hello and peace be upon you,

Let t = tables , c = chairs,

as for initial ratios,

t : c = 4 : 9

t / c = 4 / 9

t = 4c / 9 ( 1st equation);

After removing tables and chairs,

t - 2 : c - 4 = 7 : 16

t - 2 / c - 4 = 7 / 16

16(t -2) = 7(c-4)

16t - 32 = 7c - 28

16t - 7c = 4(2nd equation),

substituting (1st) into (2nd) equation,

16( 4c / 9) - 7c = 4

64c - 63c = 36

c = 36

t = 4(36) / 9 = 16

total chairs and tables = 16 + 36 = 52,

but after removing 2 tables and 4 chairs = 52 - 2 - 4 = 46,

therefore, 46 is the answer,

thanks....

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