Arrangement

Probability Level pending

Eight boys are seated in a row, find the probability that four particular boys sit together.

1 280 \dfrac{1}{280} 1 4 \dfrac{1}{4} 1 336 \dfrac{1}{336} 1 14 \dfrac{1}{14}

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1 solution

P = n o . o f f a v o r a b l e w a y s t o t a l n o . o f w a y s = 5 ! 4 ! 8 ! = P=\dfrac{no.~of~favorable~ways}{total~no.~of~ways}=\dfrac{5!4!}{8!}= 1 14 \boxed{\dfrac{1}{14}}

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