In how many ways can 5 girls and 3 boys stand in a row such that no two boys are together?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
possible Arrangement: ---girl---girl---girl---girl---girl---
--- indicates positions available for boys . As there are 3 boys and 6 positions available, arrangement of boys will be 6P3 = 120.
since 5 girls number of arrangement of girls will be 5! = 120
total ways = 5! * 6P3 = 120 * 120 = 14400.