How many integers , provided that , are there such that is a perfect square?
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A perfect square is the product of some integer with itself.
Case 1: When n = 2 k for some positive integer k
We know that
( 5 n ) 5 n = ( 1 0 k ) 1 0 k = ( ( 1 0 k ) 5 k ) 2 is a perfect square. Therefore we know that there are 100 even numbers and they all satisfy the property that ( 5 n ) 5 n is a perfect square.
Case 2: When n = 5 k 2 for some positive integer k
Similarly,
( 5 n ) 5 n = ( ( 5 k ) 2 5 k 2 ) 2 is a perfect square. Therefore the values of k such that 1 ≤ n ≤ 2 0 0 are k = 1 , 2 , . . . , 6 .
However when k = 2 , 4 , 6 , n is an even number, but we have already counted even numbers.
Thus there are 1 0 0 + 3 = 1 0 3 such numbers.