As perfect as a square! 1

How many integers n n , provided that 1 n 200 1 ≤ n ≤ 200 , are there such that ( 5 n ) 5 n (5n)^{5n} is a perfect square?

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100 200 3 103

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1 solution

Ethan Mandelez
Mar 24, 2021

A perfect square is the product of some integer with itself.

Case 1: When n = 2 k n = 2k for some positive integer k k

We know that

( 5 n ) 5 n = ( 10 k ) 10 k = ( ( 10 k ) 5 k ) 2 (5n)^{5n} = (10k)^{10k} = ((10k)^{5k})^{2} is a perfect square. Therefore we know that there are 100 even numbers and they all satisfy the property that ( 5 n ) 5 n (5n)^{5n} is a perfect square.

Case 2: When n = 5 k 2 n = 5k^{2} for some positive integer k k

Similarly,

( 5 n ) 5 n = ( ( 5 k ) 25 k 2 ) 2 (5n)^{5n} = ((5k)^{25k^{2}})^{2} is a perfect square. Therefore the values of k k such that 1 n 200 1 ≤ n ≤ 200 are k = 1 , 2 , . . . , 6 k = 1, 2, ... , 6 .

However when k = 2 , 4 , 6 , n k = 2, 4, 6, n is an even number, but we have already counted even numbers.

Thus there are 100 + 3 = 103 100 + 3 = 103 such numbers.

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