Atomic Fusion of Molecular Deuterium

Chemistry Level 2

$1) \space \space _1^2H + _1^2H \rightarrow _?^?A + _1^1p$ $2) \space \space _1^2H + _1^2H \rightarrow _?^?B + _0^1n$ $3) \space \space _?^?A + _?^?B \rightarrow _?^?C + _0^1n + _1^1p$ Two deuterium ( $_1^2H$ ) atoms have an equal chance of undergoing atomic fusion through reaction $1$ or $2$ . A third reaction occurs from the fusion of $A$ and $B$ ; the products of the first two reactions; respectively. Determine the identity of $C$ and give your answer as the $\text{mass number}$ divided by the $\text{atomic number}$ of $C$ . $Key: \\ _1^1p = proton \\ _0^1n = neutron$

David's Organic Chemistry Set

David's Physical Chemistry Set

The answer is 2.0.

1 solution

David Hontz
Jun 27, 2016

$1) _1^2H + _1^2H \rightarrow _?^?A + _1^1p \\ _{1+1-1}^{2+2-1}A = _1^3H$ $2) _1^2H + _1^2H \rightarrow _?^?B + _0^1n \\ _{1+1-0}^{2+2-1}B = _2^3He$ $3) _?^?A + _?^?B = _1^3H + _2^3He \rightarrow _?^?C + _0^1n + _1^1p \\ _{1+2-0-1}^{3+3-1-1}C = _2^4He$ $Answer: \frac{4}{2} = \boxed{2.0}$

Atomic Fusion of Molecular Deuterium

The answer is 2.0.

1 solution

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