Average acceleration

A car that is at a complete stop on a straight road starts to move. 3 3 seconds later, the speed of the car becomes 54 km/h . 54 \text{ km/h} . If the car accelerated uniformly, what is the magnitude of its acceleration for the 3 3 seconds (in m/s 2 \text{m/s}^{2} )?

5 m/s 2 5 \text{ m/s}^2 50 m/s 2 50 \text{ m/s}^2 18 m/s 2 18 \text{ m/s}^2 10 m/s 2 10 \text{ m/s}^2

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1 solution

Acceleration is given by: a = v t = 54 × 1000 60 × 60 3 = 5 m / s 2 a = \cfrac{v}{t}=\cfrac{\frac{54\times 1000}{60\times 60}}{3}=5\space m/s^2

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