Quest: - Average work done in 1 Day (1st) = 1 unit. Average work done in 2 Days (1st & 2nd) = 1 unit. Average work done in 3 Days (1st, 2nd & 3rd) = 4/3 units. Average work done in 4 Days (1st, 2nd, 3rd & 4th) = 7/4 units. Based on above pattern, find the average work done in 10 Days (1st, 2nd… 9th & 10th Day)?
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The general formula for the average work done can be calculated using the formula i = 1 ∑ n i F i , where F n denotes the n th Fibbonacci number.
So, average work done in 1 0 days is i = 1 ∑ 1 0 1 0 F 1 0 = 1 0 1 + 1 + 2 + ⋯ + 5 5 = 1 0 1 4 3 = 1 4 . 3