Average Velocity of Object
Calculus
Level
2
If there was object that travels a distance of s(t) = 2t^2 - 5t +1, where as s is in feet and t is in seconds. Find: The average velocity of object within the first 10 seconds.
15 feet per second
5 feet per second
-15 feet per second
0 feet per second
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1 solution
when t=0 then s=2 * 0^2 + 5 * 0 +1 = 1 feet , when t=10 then s= 2 * 10 ^ 2 + 5 * 10 + 1 = 151 feet . so total distance cover in first 10s is=(151-1)=150 feet . so avg velocity=150/10=15 feet/sec