Avi's challenge part 1
Probability
Level
3
Find the number of ways in which the number, 30 can be partitioned into three unequal parts, each part being a natural number.
The answer is 61.
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1 solution
Let.the numbers be a,b,c a+b+c=30 Since they have to.be natural numbers a+b+c=27 Number of ways to divide 30 unequally is (29c2- 1- 3*13)/3!= 61