A bacteria multiplies twice in number per second. For example. If there were 2 bacteria in the first second, then in the next second there are 4, and in the next, 8 and so on.....
Now, If a jar was completely full with the bacteria on SECOND 60. How much is the jar full on SECOND 57?
Answer is decimals......
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Let x be the volume occupied at the 60th second by the bacteria that grew inside the jar. As their growth is expressed mathematically as a geometric progression with reason q=2 , the volume occupied in the 59th second will be x/2 , because, if x/2 is the 59th term, the next term, which is x , will be x/2 x 2, which is equals to x. Then, dividing x/2 by 2, comes x/4, which is the 58th term. Dividing it by 2 once again, comes x/8, which is 0,125 . That's the volume occupied by the bacteria at the 57th second after the growth's "t=0".