Bacteria Reproduction

Level pending

The rate of growth of bacteria is proportional to the number of bacteria present. Under suitable growth conditions, the Lactic Acid Bacteria (LAB) double every hour. If there was initially 1 bacteria, how many bacteria will be present after 9 hours ?

36 18 512 90

Soham Zemse by Soham Zemse , 24, India

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3 solutions

Kesavan Subburam
Feb 18, 2014

Bacteria divides by binary fission. So the growth is exponential. The solution can be found by the

f u n c t i o n g r o w t h = 2 N function growth = 2^{N}

where N is the number of cycles of bacterial division.

N = t o t a l t i m e t a k e n d o u b l i n g t i m e N = \frac{total time taken}{doubling time}

N = 9 h 1 h N = \frac{9h}{1h}

N = 9

2 9 = 512 2^{9} = 512

3 Helpful 0 Interesting 0 Brilliant 0 Confused
Priya Dwivedi
Jan 2, 2014

rate of growth=k*no of bacteria ; initially no of bacteria =1 every hour no of bacteria doubles i.e k=2 so after 9 hours no of bacteria will be pow(2,9).

3 Helpful 0 Interesting 0 Brilliant 0 Confused
Meldrin Rebello
Mar 9, 2014

2 power 9 = 512

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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