Starting on 1st day with 1 organism of type A. Organism of type A multiply themselves each day, such that next day, thrice as many organisms are present. However, one of the organism underwent a mutation on the 3rd day and multiplied only twice a day. How many organisms are there at the end of a week from the starting, assuming that mutated organisms cannot produce organisms of type A and no further mutations take place.
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Till third day, bacteria A=8, B=1.
On 7th, A = 8 × 3 4 , B = 1 × 2 4 . So total bacteria= 6 4 8 + 1 6 = 6 6 4