Bacterial Progressions

Algebra Level 2

Starting on 1st day with 1 organism of type A. Organism of type A multiply themselves each day, such that next day, thrice as many organisms are present. However, one of the organism underwent a mutation on the 3rd day and multiplied only twice a day. How many organisms are there at the end of a week from the starting, assuming that mutated organisms cannot produce organisms of type A and no further mutations take place.


The answer is 664.

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1 solution

Prince Loomba
Oct 9, 2016

Till third day, bacteria A=8, B=1.

On 7th, A = 8 × 3 4 , B = 1 × 2 4 A=8×3^{4}, B=1×2^{4} . So total bacteria= 648 + 16 = 664 648+16=664

I only mention that the problem is not realistic. Maybe the bacteria are aliens?

Andreas Wendler - 4 years, 8 months ago

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Yes maybe, lemme change

Prince Loomba - 4 years, 8 months ago

Howw is it now?

Prince Loomba - 4 years, 8 months ago

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Now it is very fine!

Andreas Wendler - 4 years, 8 months ago

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