In the above diagram, both beams are balanced.
How many red squares will it take to balance 1 semi-circle?
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What you're calling a 'diamond' is actually a square!
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Thanks. I have edited the problem accordingly.
As I cannot use square again I used diamond.
Sorry for that. I wasn't thinking of the diamond as a square. Thanks for pointing it out :)
This question is great!
its awesome
well done sravanth i really admire your approach through variables
and by the way how can i change my profile pic ?
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Do a simple relation between yellow and red pieces: 1 yellow wheighs 2 reds. That said, if you subtract 1 yellow and the 2 reds of the second scale, it gives off the correspondence: 1 purple equals 2 yellow, therefore, 1 purple equals 4 reds
1 diamond=2 square so,in the 2nd balance 2 square equals to 1 diamond. Therefore, 1 semi-circle equals to 2 diamonds. and 2 diamonds = 2*2squares=4 squares.(1 diamond =2squares) so to balance the semi circle by the squares, we need 4 red squares. :)
Call the yellow square a, the red square b and the semicircle c. Firstly we can create two linear equations:
a = 2b [1]
2b + c = 3a [2]
Equation 2 can be substituted into equation 1:
2b + c = 3(2b) = 6b
This is then rearranged to form an equation for c, in b:
c = 4b
Hence 4 red squares balance one semicircle
If one Y is 2R
Then 3Y is 6R
6R-2R=4R
Therefore the semicircle is worth 4 Red Squares in weight
1 rhombus = 2 squares
3 rhombus = 1semi-circle + 2 squares
then 2 rhombus = 1 semi-circle
1 semi-circle = 4 squares
Nice and clear!
Did you know that the yellow thing is also a square? Rotated square?
One diamond is equals to two square. Accordingly in second beam 3 diamonds equal to 6 squares then we can cross 2 square both side this means I half sphere equal to 4 square.
2 red squares = 1 yellow squares.here 2 red squares balance 1 yello square. so 2 yellow squares balance the semi circle. 2 yellow squares means 4 red squares
What I did is this that.... here its shown that "1 diamond=2 squares. In the second image we see that 3 diamonds are here which means 30 or we can say its 3*2 = 6 squares. now the 6 squares=1 semicircle + 2 squares so, 6 squares - 2 squares = 1 semicircle = 4 squares. This question can be attempted in mind .
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Let us represent diamond as d, square as s and the semi circle as c.
We know that d = 2 s . . . . . . . . . (i)
Now, c + 2 s = 3 d
Or, c + d = 3 d . . . . . . . . . . . .[from (i)]
Or, c = 2 d
Now, from (i), 2 d = 4 s
Therefore, the number of squares required to balance a semicircle is, 4