Balls and Boxes gone crazy. Part-IV
Probability
Level
3
Five balls are to be places in three boxes. Each can hold all the five balls. In how many different ways can we place the balls so that no box remains empty, if balls as well as boxes are identical ?
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The answer is 2.
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1 solution
possible ways are 122,113,131,212,311,221
But here ordering of boxes doesn't matter, hence 121 is equivalent to 212 and 221
This implies that, total number of ways = 6/3 =2