What single digit number would need to be subtracted from the following base 13 number to make it divisible by 13?
98743298742734987547657644211154547
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Sure thing... In base 13, reading the digits from right to left, this number is equal to 7 ∗ 1 3 0 + 4 ∗ 1 3 1 + 5 ∗ 1 3 2 + 4 ∗ 1 3 3 + . . . . And all except for the first element, 7 x 1 3 0 , divide by 13. Therefore, if we subtract 7, that element goes away and then the number is divisible by 13.
It's similar to how any number in decimal that ends with a zero divides by 10.
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Any base n number will be divisible by n if, and only if, the number ends in 0. So subtracting 7 will do the job! :)