Suppose that % , # , @ and £ are symbols used to represent digits in base 2018 with the following properties:
% - # = @
% + # = @ + £
%# - #% = £@
What are the last 4 digits of the decimal representation of %£ - @# ?
Note: Remember that the symbols are digits, and therefore %# should not be read as % * # , in the same way that 12 is not read as 1 * 2
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If we take the information from the question and put it into an algebraic format we get,
% - # = @ (1)
% + # = @ + £ (2)
2018% + # - 2018# - % = 2018£ + @
which rearranged and factorised gives us,
2017(% - #) = 2018£ + @ (3)
Substituting ( 1 ) into ( 3 ) ,
2017@ = 2018£ + @
2016@ = 2018£
1008@ = 1009£
As all symbols must be between 1 and 2 0 1 7 as they are in base 2 0 1 8 . Also, 1 0 0 8 and 1 0 0 9 are coprime, meaning the only possibility is £ = 1 0 0 8 and @ = 1 0 0 9 .
( 1 ) + ( 2 ) ,
2% = 2@ + £
Meaning that we can substitute in, and find that the values are % = 1 5 1 3 and # = 504 .
Placing these values into the final expression gives us a decimal value of 1 0 1 7 5 7 6 , meaning the answer is 7 5 7 6 .