Base Changing Breakdown

In the following argument in which step has a mistake been made:

let logₘn = a

changing the base to 10 gives

  1. a = l o g n l o g m \frac{log₁₀n}{log₁₀m}

  2. a = log₁₀( n m \frac{n}{m} )

  3. 10ᵃ = n m \frac{n}{m}

however changing the base to 11 instead of 10 gives

11ᵃ = n m \frac{n}{m}

thus 10ᵃ = 11ᵃ

  • or 10 = 11 !


The answer is 2.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Edwin Fernando
Jun 20, 2020

Quite a simple mistake has been made in step 2 of this problem:

l o g n l o g m \frac{log₁₀n}{log₁₀m} ≠ log₁₀ n m \frac{n}{m}

A fraction with the logarithms of two values as the numerator and denominator, is not the same as the logarithm of a fraction with those same values as the numerator and denominator.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...