Who Speaks In Different Bases?

Jam, Jim, and John count in binary, hexadecimal and decimal respectively.

Jam says "I have 101 trading cards."
Jim says "Me too!"
And John says "So do I!"

In decimal representation, how many do they have altogether?


Try more questions on Bases


The answer is 363.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Chung Kevin
Apr 14, 2016

The total number of trading cards Jam has is 10 1 2 101_2 .
The total number of trading cards Jim has is 10 1 16 101_{16} .
The total number of trading cards Jim has is 10 1 10 101_{10} .

Let's convert all of these numbers to decimal numbers.

10 1 2 = 1 ( 2 2 ) + 0 ( 2 1 ) + 1 ( 2 0 ) = 5 10 1 16 = 1 ( 1 6 2 ) + 0 ( 1 6 1 ) + 1 ( 1 6 0 ) = 257 10 1 10 = 1 ( 1 0 2 ) + 0 ( 1 0 1 ) + 1 ( 1 0 0 ) = 101 \begin{array} {l c l l } 101_2 &=& 1(2^2) + 0(2^1) + 1(2^0) &= 5 \\ 101_{16} &=& 1(16^2) + 0(16^1) + 1(16^0) &= 257 \\ 101_{10} &=& 1(10^2) + 0(10^1) + 1(10^0) &= 101 \end{array}

Thus, in decimal representation, the total number of trading cards Jam, Jim and John have is

5 + 257 + 101 = 363 . 5 + 257 + 101 = \boxed{363} \; .

Geoff Pilling
Apr 12, 2016

101 equals 257 in hexadecimal, 101 in decimal, and 5 in binary. So all together they have 257+101+5 = 363 trading cards.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...