Base

If the decimal number 212 is written in base n n , then it is in form of 2121 2 n 21212 _n , find n n .

3 4 7 2 9

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1 solution

Alex G
May 27, 2016

Since the number uses 2 as a digit, n > 2 n>2 .

The number is equivalent to 2 + n + 2 n 2 + n 3 + 2 n 4 2+n+2n^2+n^3+2n^4 . As such, n 4 < 212 n^4<212 . Note that 4 4 = 256 4^4=256 , therefore n < 4 n<4 . Since 2 < n < 4 2<n<4 and n is an integer, n = 3 \boxed {n=3} .

Never thought of it like this. Good Job.

Hana Wehbi - 5 years ago

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Thank you again. Bases are a passion of mine.

Alex G - 5 years ago

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You are welcome. I will try to post more nice problems about bases.

Hana Wehbi - 5 years ago

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