Basic chemistry-1

Chemistry Level 1

what will be the p H p^H for 0.0003 M S r ( O H ) 2 Sr(OH)_2 solution?

11.182 8.568 13.765 10.778

Mohammad Khaza by Mohammad Khaza , 20, Bangladesh

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1 solution

Mohammad Khaza
Jan 11, 2018

here, [ O H − OH^- ]= 2 × 0.0003 = 0.0006 2 \times 0.0003=0.0006

so, p O H = − l o g [ O H − ] = − l o g ( 0.0006 ) = 3.22 p^{OH}=-log[OH^-]=-log(0.0006)=3.22

and so, p H = 14 − p O H = 14 − 3.22 = 10.778 p^H=14-p^{OH}=14-3.22=10.778

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