Basic Concept of Thermal Conductivity.

The given figure shows a composite slab of three different materials, a, b, and c with identical thickness and with thermal conductivity k b > k a > k c k_b > k_a > k_c . The transfer of energy through them as heat is non-zero and steady. The temperature difference across material a, b and c are Δ T 1 \Delta T_1 , Δ T 2 \Delta T_2 and Δ T 3 \Delta T_3 respectively. Then :

Δ T 1 = Δ T 2 = Δ T 3 \Delta T_1 = \Delta T_2 = \Delta T_3 Δ T 3 < Δ T 1 < Δ T 2 \Delta T_3 < \Delta T_1 < \Delta T_2 Δ T 1 < Δ T 2 < Δ T 3 \Delta T_1 < \Delta T_2 < \Delta T_3 Δ T 2 < Δ T 1 < Δ T 3 \Delta T_2 < \Delta T_1 < \Delta T_3

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...