basic equation 2.

Given:

$X+Y=22$

$X-Y=18$

Substituting, we get:

$X+Y=22$

$X=22-Y$

Putting $X$ in the second equation.

$X-Y=18$

$22-Y-Y=18$

$-2Y=18-22$

$-2Y=-4$

$Y=2$

So, $X=22-Y=22-2=20$

So, $XY=20\times2=40$

Thus, the answer is: $XY=\boxed{40}$

$Given\quad that\\ x+y=22\quad ............\quad (i)\\ x-y=18\quad .............\quad (ii)\\ Adding\quad (i)\quad \& \quad (ii),\quad we\quad have\\ \boxed { x=20 } \\ Subtracting\quad (i)\quad \& \quad (ii),\quad we\quad have\\ \boxed { y=2 } \\ Now,\\ xy=(20)(2)\\ \boxed { xy=40 }$

$x+y=22$ .................[1]

$x-y=18$ ..................[2]

so, adding [1]+[2] we get,

$x+y+x-y=22+18$

or, $2x=40 , or, x=20$

so, $y=2$ and $xy$ = $20 \times 2=40$

Adding both the equations, we get, 2X =40

X = 20 & Y= 2

XY = 20 x 2 = 40

Add the equations to get:- $2x = 20\\ x = 20$ .
So, $20 + y = 22\\ y = 2\\ \implies xy = 20 × 2\\ xy = \color{#69047E}{\boxed{40}}$

Treat this as a equation and add them together so X+X+Y-Y=22+18. The Ys cancel out and you are left with 2X=40. Divide each side by 2 and X=20. Now plug it in on of the equations: 20+Y=22. Y=2. Now you can multiply them together just what the question asked for.

Solving the first 2 equations, we get 'X=20' and substituting value of 'X' in any of the first 2 equations, we get 'Y=2' And finally 'XY = 20x2 = 40'

By subtracting we get value of X =2= and substituting this in given equation value of Y is 2 So value of XY =40 Ans

KKGARGIndia

20+2=22 and 20-2=18 so x=20 and y=2 so xy i.e. Xxy=20x2=40