Basic Locus Problem

Geometry Level 4

P moves in a plane such that PA=λPB,where A,B are fixed points and λ>0.Which of the following can be locii for P?

parabola ellipse hyperbola circle,straight lines

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Tom Engelsman
Oct 18, 2015

Let P(x,y) be any point in the xy-plane, and let A(-c/2,0), B(c/2,0) be two fixed points on the x-axis. We are told |PA| = k*|PB| (k > 0). This can be expressed as:

sqrt[(x + c/2)^2 + y^2] = k*sqrt[(x - c/2)^2 + y^2];

or (x + c/2)^2 + y^2 = k^2 * [(x - c/2)^2 + y^2];

or x^2 +cx + c^2/4 + y^2 = k^2 *(x^2 - cx + c^2/4 + y^2);

or 0 = (k^2 - 1) x^2 - c (k^2 + 1) x + (k^2 - 1) y^2 + (k^2 - 1)(c^2/4);

or 0 = x^2 - c [(k^2 + 1)/(k^2 - 1)] x + y^2 + c^2 /4;

or (c^2/4) [(k^2 + 1)/(k^2 - 1)]^2 - c^2/4 = {x^2 - c [(k^2 + 1)/(k^2 - 1)] x + (c^2/4) [(k^2 + 1)/(k^2 - 1)]^2} + y^2;

or k [c/(k^2 - 1)]^2 = [x - (c/2) [(k^2 + 1)/(k^2 - 1)]]^2 + y^2.

We ultimately end up with a locus that resembles (x - a)^2 + (y - b)^2 = r^2, or a circle.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...