An algebra problem by Jax Lincoln

Algebra Level 2

In an urn, 4 7 \frac{4}{7} of the chips are red and the rest are blue. If the number of red chips is reduced by half and the number of blue chips is doubled, what is now the fraction of red chips in the urn?

1 3 \frac{1}{3} 2 7 \frac{2}{7} 1 4 \frac{1}{4} 1 2 \frac{1}{2}

Jax Lincoln by Jax Lincoln , 19, Philippines

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1 solution

Jax Lincoln
Oct 15, 2017

If 4 7 \frac{4}{7} chips are red ,

then 3 7 \frac{3}{7} chips are blue .

So, there are 7 chips in all; 4 are red and 3 are blue.

"red chips are reduced to half"

4 2 \frac{4}{2} = 2 red chips

"blue chips are doubled"

3 × 2 3 \times 2 = 6 blue chips

2 red chips + 6 red chips = 8 chips (total)

There are 2 8 \frac{2}{8} = 1 4 \frac{1}{4} red chips

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grabe bright

mac louie morabor - 3 years, 7 months ago

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