Basic Proofs!!!

Calculus Level pending

How you will prove that,

Derivative of e^x = e^x

Draw the graph and work out gradient Use Pythagoras Identity and do some trigonometry Take log to e^x then use chain rule and equate with 1 to get answer Take log of e^X then use Quotient Rule and equate with one It is easy to say this so who cares about proof

Syed Baqir by Syed Baqir , 24, Cyprus

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jihoon Kang
Apr 11, 2015

I would personally use the maclaurin explansion of e x e^{x} = 1 + x + x 2 2 ! + x 3 3 ! + x 4 4 ! . . . =1+x+\frac{x^{2}}{2!}+\frac{x^3}{3!} +\frac{x^4}{4!}...

Differentiating this: 0 + 1 + x + x 2 2 ! + x 3 3 ! + . . . 0+1+x+\frac{x^{2}}{2!}+\frac{x^3}{3!} +... = e x e^{x}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...