Basic uniform acceleration

Classical Mechanics Level 1

A constant net force is applied to an object, causing it to accelerate with magnitude of acceleration $a.$ What will be the magnitude of acceleration if the force is doubled and the object’s mass is halved?

a 2a 4a

\frac{a}{2}

3 solutions

Jrenz Salvador
Jun 5, 2014

From Newtons 1st Law F = force and m = mass of the object

F = ma (2)F = (m/2)*a

a = 4F/m

a = 4a

Sanchita Seth
Jun 4, 2014

Let the constant net force be F and mass of object be m

Therefore acceleration a can be written as F/m (from the newton's law F=m*a)

Now, the Force was doubled i.e., force= 2F And, the Mass was halved i.e., mass=m/2

Therefore the new acceleration, A can be written as : A = force/mass

A=2F/(m/2)

A=4*(F/m)

A = 4*a [ as a=F/m]

Hence the magnitude of acceleration is 4a

Jaivir Singh
Jun 27, 2014

WHEN FORCE IS DOUBLE AND MASS HALF THEN ACC BECOMES 4 TIMES

Basic uniform acceleration

3 solutions

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