Basics of Derivative

$(x-1)(x+3)=x^{2}+2x-3$ The derivative of this is $2x+2$

If you hadn't noticed already, the sum of (x - 1) and (x + 3) is (2x + 2).

This is because an easy way to do this differential involves adding them after multiplying each of them by the differential of the other, which happens to be 1.

$f(x)=(x-1)(x+3)$

By the product rule, we have

$f'(x)=(x-1)(1)+(x+3)(1)$

$f'(x)=x-1+x+3$

$f'(x)=2x+2$

easiest way to solve it was using the FOIL method of multiplying polynomials but only solve for the 1st and 2nd term. x*x = x^2 derivative is 2x 2nd term is = to [3+(-1)]x = 2x derivative is 2

d/dx(x^2+2x-3) =2x+2

Derivative of X^2+2x-3=2x+2