Batman!

Classical Mechanics Level 3

Batman, whose mass is 80.0 kg 80.0 \textbf{ kg} is dangling on the free end of a 12 m 12 \textbf{ m} rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually making it swing enough that he can reach a ledge when the rope makes a 6 0 ∘ 60^\circ angle with the vertical. How much work was done by the gravitational force on Batman in this maneuver in Joules \textbf{Joules} ?

9 = 9.8 m s − 2 9 = 9.8 m s^{-2}


The answer is 4704.

Samuel Ayinde by samuel ayinde , 24, Nigeria

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1 solution

Varun Bansal
Jun 29, 2014

gravitational force is always downwards. hence, work done by it is by force acting against it [its' mass = 80 Kg. ] to move it vertically up wards [i.e., = 12-(12 cos 60) = 6 mts.] . Hence work = M G H =80 9.8 6=4704

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Although the problem is correct , you should state that g=9.8 m/s

Aishwary Omkar - 6 years, 8 months ago

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