BdMO Problem 1
Level
pending
Four of the six numbers 1928, 1938, 1981, 2031, 2069 and 2117 have a mean of 2013. What is the mean of the other two numbers?
The answer is 2006.
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1 solution
Sum of all numbers = 1928+1938+1981+2031+2069+2117 = 12064
Sum of the 4 numbers having mean of 2013 = 4 x 2013 = 8052
So the sum of rest 2 numbers = 12064 - 8052 = 4012
So the mean of the 2 numbers = 4012/2 = 2006