In rectangle ABCD, Q is a point located inside in such a way that PQ is perpendicular to AB and P point is on AB. Rectangle ABCD is divided into two regions, APQCD and PBCQ of equal area. If PB = 4,AD = 8 and PQ = 3,what is the area of ABCD?
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Area of trapezium PBCQ = 1/2 x (PQ + BC) x PB = 1/2 x (3 + 8) x 4 = 22 ( Bcoz BC = AD in rectangle ABCD)
Also given, Ar(APQCB) = Ar(PBCQ)
So, Ar(ABCD) = Ar(APQCB) + Ar(PBCQ) = 22 + 22 = 44