Jon drives from his home to the store at an average speed of kilometers per hour. He drives back home from the store at an average speed of kilometers per hour. Assume the distance he travels in these two trips is the same. His average speed for the entire trip is how many kilometers per hour?
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Let x be the distance. So time for forward drive is x/40 hr. For back it is x/60.
A v e r a g e s p e e d = t o t a l t i m e t o t a l d i s t a n c e = 4 0 x + 6 0 x 2 x = 4 8 4 8