Be careful about probabilities

Suppose 2 integer are chosen from between 1 and 9,inclusive. What is the probability that they are both odd?

0.550 0.277 0.275 0.555

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2 solutions

Roger Erisman
Apr 12, 2020

Choose first odd integer in 5 of 9 ways.

Choose second odd from remaining in 4 of 8 ways.

5/9 * 4/8 = 20/72 = .27777

A pair of odd integers from the given numbers can be chosen in 10 10 ways. Two integers can be chosen in 36 36 ways. Therefore the required probability is 10 36 0.277777 \dfrac{10}{36}\approx \boxed {0.277777} .

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