A doctor soaks a cast with body-temperature water and wraps it around a patient’s arm. As the cast begins to set, does the patient feel a difference in temperature?
Note: This is a hydration reaction. As the cast hardens, water molecules "attach themselves" to the cast.
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I have a live experiance :P
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Oh, well. Was it getting warmer then?
I solved it the same way. ;)
you did not say it was exothermic.
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I did not know a hydration reaction was exothermic you tricked me. So if I make a mud patty on the sidewalk and exclude the temperature of the sun and just consider the hydration reaction that is taking place it will generate heat?
So there is no excess water? Would that change things?
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Practically, by soaking it, there will be just enough water to be absorbed in the chemical reaction. So no to your inquiry. :)
So why am I wrong when I choose "Yes, their arm should feel warmer"?
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Well, that is the correct answer given by the site.
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Yes, but it seems I can be correct and incorrect at the same time.
Surely then it would feel warm at first but while it dries up it would feel cold, because the drying up is the endothermic reaction taking place like you said? The hydration reaction takes place when the doctor soaks the cast with water, hence the process of it drying out must be the reverse of this hydration. It’s a bit confusing because the point in time when the patient feels the difference in temperature is a bit delayed (first some heat energy is released and then it is absorbed again later on) but during the literal process of it drying out, it should become colder again.
The hydration reaction is an exothermic reaction i.e. heat is released during this process. As a result, the patient should feel warm.
If heat is released, shouldn't heat be lost to the surroundings? I am quite confused why temperature drops in an endothermic reaction and the converse in an exothermic one? I am really quite inexperienced at this so please forgive the naivety!
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I was confused at first too,but if you think about it the heat released gets trapped within the area covered by the plaster causing the temperature to increase. Note: that's just my guess I am not a 100 percent sold on that theory of mine.
in the exothermic reaction of the cast, heat is released to the surrounding (air and your arm). your arm will be "receiving" that heat and thus you'd feel warmer.
The still unbound water molecules move freely with a specific (translational) kinetic energy determined by the water temperature.
2 1 m H 2 O ⋅ ⟨ v 2 ⟩ = 2 3 k B T
with m H 2 O being the mass of a water molecule, ⟨ v 2 ⟩ the mean square velocity of all water molecules, k B being the Boltzmann constant and T being the temperature.
When, during the hydration reaction, the water molecules attach to the cast , this translational kinetic energy needs to go somewhere. It is converted to rotational and vibrational energy (other degrees of freedom which are strictly speaking also kinetic energy) of the cast which corresponds to an increase in temperature on a macroscopic level.
In other words: By taking the more energetically favorable form of the water bound to the cast, excess energy is freed. It is released in the form of heat and increases the temperature of the plaster.
Very good explanation sir. Thanx for this effort
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Rubbish! Put away your silly maths! I had a plaster cast on my broken leg and it felt cooler.
great explanation.
A more simplistic answer is that the cast will prevent the arm losing any heat naturally to the air, thus feeling warmer regardless of any exothermic reaction.
If the reaction was endothermic, then it would be difficult to predict the arm will feel warmer or cooler.
I only knew the answer as I've had a cast applied before, and can recall the effect of the hydration reaction.
Let’s just remember what happened by understanding that creating a bond release energy while breaking a bond need energy. Let’s say the system is water and the bandage while the surrounding is your hand. So the water is attached to bandage which means inside the system, they create bond and release energy. As a result, the reaction is exothermic and the surrounding (your hand) receive heat and feel warmer
Try guessing sometimes also theres a thing called warm water .... it happens when water gets in contact with warm stuff like skin..... yeah
Spontaneously, things give off heat unless they can absorb it to move to a more disordered state. This is quantified by the difference in Gibbs free energy, Δ G = Δ H − T Δ S , which determines if a reaction occurs spontaneously Δ G < 0 or not Δ G > 0 .
If the water molecules attach themselves to the cast, they become more ordered than when they are flowing around. Because entropy decreases and the reaction still happens, it must give off heat.
Experienced it myself after an accident
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A classic plaster cast is made of bandage and heated gypsum, a form of calcium sulfate, though a modern cast may contain fiberglass to improve the strength and stability within the cast.
When this dehydrated gypsum reacts with water, the water molecules are absorbed and chemically aligned among the calcium sulfate crystals. This process is an exothermic reaction, meaning giving out heat, as new chemical bonds are created:
2 ( C a S O 4 ⋅ 2 1 H 2 O ) + 3 H 2 O → 2 ( C a S O 4 ⋅ 2 H 2 O ) + △
As a result, while the plaster cast dries up (absorbing water) and hardens into a stronger gypsum form, the patient will feel the warmth gradually coming out of the structure, which will last within 10 minutes.
Moreover, the counterpart of this reaction is called endothermic , literally absorbing in heat, where the chemical bonds are broken into ion forms. An explicit example is when salt is put into the ice water in the bucket, the temperature inside will drop even to the point where it freezes the surrounding. (This is how scientists show how to make juice sherbet sticks to the kids.)
Conversely, this happens because when salt (Sodium chloride) is dissolved in water, its molecules break down into sodium and chloride ions, its core elements, and to do so, they use the energy or heat from the surrounding water molecules, causing the water molecules to be less agile or cooler in the process.