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Let us convert these decimals into fractions instead, which will make the calculation much easier.
0 . 3 represents the repeating decimal number, 0 . 3 3 3 3 3 … = 0 . 3 + 0 . 0 3 + 0 . 0 0 3 + ⋯ , which represents a geometric progression sum , with first term of a = 0 . 3 and common ratio of r = 0 . 1 , thus the sum of this geometric progression is 1 − r a = 1 − 0 . 1 0 . 3 = 0 . 9 0 . 3 = 9 3 = 3 1 .
This means that 0 . 3 = 0 . 3 3 3 3 3 … = 0 . 3 + 0 . 0 3 + 0 . 0 0 3 + ⋯ = 3 1 .
Similarly, we can also show that 0 . 6 = 0 . 6 6 6 6 6 … = 0 . 6 + 0 . 0 6 + 0 . 0 0 6 + ⋯ = 1 − 0 . 1 0 . 6 = 0 . 9 0 . 6 = 9 6 = 3 2 .
In short, what we have obtained is that 0 . 3 = 3 1 and 0 . 6 = 3 2 .
And we just need to add these two fractions up:
0 . 3 + 0 . 6 = 3 1 + 3 2 = 3 1 + 2 = 3 3 = 1
And so, our answer is 1 .
Footnote :
We can write 0 . 3 as 0 . 3 3 3 … and 0 . 6 as 0 . 6 6 6 … . Therefore adding these two values we get 0 . 3 3 3 … + 0 . 6 6 6 … = 0 . 9 9 9 … . But the provided answer is 1 . To check 0 . 9 9 9 … = 1 , you might want to visit is 0.999... = 1? .
To know how to convert repeating decimals into fractions, you may visit the wiki page: Converting repeating decimals into fractions .