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1 solution
2 0 1 7 ≡ 4 6 ≡ 1 ( m o d 3 ) . Therefore,
2 0 1 7 4 6 − 4 6 ≡ 1 4 6 − 1 ≡ 0 ( m o d 3 ) .
Thus, 2 0 1 7 4 6 − 4 6 is divisible by 3 (but is certainly not equal to three), so it is not prime.