Beauty in Symmetry

Algebra Level 2

{ x + y + z + 18 a + b = 135802458 x + y + 18 z + a + b = 135802458 18 x + y + z + a + b = 135802458 x + 18 y + z + a + b = 135802458 x + y + z + a + 18 b = 135802458 \begin{cases} x + y + z + 18a + b = 135802458 \\ x + y + 18z + a + b = 135802458\\ 18x + y + z + a + b = 135802458\\ x + 18y + z + a + b = 135802458\\ x + y + z + a + 18b = 135802458 \end{cases}

Solve the system of equations above for real values of x x , y y , z z , a a , b b .

Enter the value of x x as your answer.


The answer is 6172839.

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1 solution

Abhinav Raichur
Feb 20, 2016

Observing the symmetry in the equation, we see that interchanging the values of x x , y y , z z , a a , b b cyclically in the first equation will yield b + x + y + 18 z + a = 135802458 b + x + y + 18z + a = 135802458 which is the second equation. Similarly, interchanging the variables in cyclical manner would yield all the 5 equations in some order. This shows that all the variables have to be equal. putting x = y = z = a = b x= y = z = a = b
22 x = 135802458 22x = 135802458 x = 6172839 x = 6172839

Yay! Same method!

Nihar Mahajan - 5 years, 3 months ago

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Thanks for your comment :) ... No matter how complex math we know and understand... These are the things I love the most.... How did you find it?

Abhinav Raichur - 5 years, 3 months ago

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There is always beauty in symmetry :P

Nihar Mahajan - 5 years, 3 months ago

Same way dude!!!

abc xyz - 5 years, 3 months ago

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@abc xyz cool :) ... Thanks for your comment

Abhinav Raichur - 5 years, 3 months ago

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