For x ∈ ( 0 , 1 ) , if f ( x ) = n − k x and g ( x ) = 1 + k x for n > 0 , k ≥ 0 some consecutive integers, n > k n = 1 ∑ ∞ 2 n 2 ( − 1 ) n ∫ 0 1 ( ln f ( x ) + 2 ln g ( x ) ) d x = − ζ ( 2 ) η ( 2 ) ln ( 2 ζ ( 4 ) 1 m ≥ 1 ∏ m 2 m 2 ) = η ( 2 ) ln ( A 2 2 2 e γ π ) Is the above closed form is correct?
where ζ ( . ) is Riemann zeta function η ( . ) is Dirichlet eta funtion , A is Glashier-kinkelin constant , γ is Euler-Mascheroni constant and e is Euler-number
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The correct closed form of it is − ζ ( 2 ) η ( 2 ) ln ( 2 ζ ( 2 ) 1 m ≥ 1 ∏ m 2 m ) = η ( 2 ) ln ( A 1 2 4 e γ π )