As shown in the figure, a circle centered at bears a point hosting a line tangent to the circle. Can you find out the equation of that tangent line without using calculus?
If the equation of the line can be expressed in the form , where , and are integers and , then enter as your answer.
Notations :
denotes the greatest common divisor function.
denotes the absolute value function .
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Now By Our Method without Calculus , We Need The Straight Line Knowledge.
Now the slope of the line O P is 1 1 − 5 / 8 − 3 = 6 / 5
Now We know that P is a point on the tangent , then O P is the normal of the tangent
Now we know for Perpendicular lines m 1 ∗ m 2 = − 1 .
Hence Slope of the tangent is − 5 / 6 .
Now we will put in two point form to get
=> y − 1 1 / x − 8 = − 5 / 6
Now after solving this equation we get a equation. Now we will compare the equation with a x + b y + c = 0 to get ∣ a b c ∣ = 3 1 8 0 .