Beginners A A gebra 3: Multiplication

Algebra Level 1

3a x 2b is 6ab

lets break it up

(3a) = 3 x a

(2b) = 2 x b

therefore: 3a x 2b = 3 x a x 2 x b

lets times the numbers first

3 x 2 = 6

now the letters

a x b = ab

remember it does not matter what order you put the letters ab = ba

abx 6 = 6ba

if two like terms times each other it will be similar except for the pronumeral part i will now give an example below:

4a x 4a

lets break it up

(4a) = 4 x a

(4a) = 4 x a

therefore: 4a x 4a = 4 x 4 x a x a

4 x 4 = 16

a x a = a 2 ^{2}

therefore

a 2 ^{2} x 16 = 16a 2 ^{2}

now for the problem:

Remember to still use BODMAS or BIDMAS

what is 7a x (b x (6 x 3)) x 2a = ?

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7a -b + 36a a 2 ^{2} 7b 7b632a 252a 2 ^{2} b

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2 solutions

Lâm Lê
Nov 1, 2020

7 a × ( b × ( 6 × 3 ) ) × 2 a = 7 a × 18 b × 2 a = 252 a 2 b 7a×(b×(6×3))×2a=7a×18b×2a=\color{#00ff00}\boxed{252a^2b}

Nscs 747
Oct 28, 2020

so we have this : 7a x (b x (6 x 3)) x 2a = ?

lets do the brackets first

6 x 3 = 18

18 x b = 18b

now we are left with: 7a x 18b x 2a = ?

now we just times them together

7a x 18b = 126ba

now times this by 2a

126ba x 2 = 252ba

but wait! what about the "a" from 2a?

well from what we learn earlier if a pronumeral ties itself it is squared so a x a = a 2 ^{2}

so that leaves us with 252a 2 ^{2} b

hope you enjoyed this problem!

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