Bending of Light rays!

If light passes near a massive object, the gravitational interaction causes a bending of the ray. This can be thought of as happening due to a change in the effective refractive index of the medium given by n ( r ) = 1 + 2 G M r c 2 \large n(r) = 1 + 2\frac{GM}{rc^2} where r r is the distance of the point of consideration from the center of the mass of the massive body, G G is the universal gravitational constant, M M the mass of the body and c c the speed of light in vacuum. Considering a spherical object, find the deviation of the ray θ 0 \theta_0 from the original path as it grazes the object.

If θ 0 = n 1 G M r c n 2 \large \theta_0 = n_1\frac{GM}{rc^{n_2}} , find n 1 + n 2 n_1 + n_2 .


The answer is 6.

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