A number theory problem by Kushagra Sahni

Find the number of zeroes at the end of

Product of 1, 2, 3, 4, ..................1994


The answer is 495.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Satvik Golechha
Feb 14, 2014

WRONG QUESTION !! The question should've been "number of zeroes at THE END OF" and not "no of zeroes in"

Shall I show you the book from which this question has been copied. In fact it is an RMO problem of the year 1994.

Kushagra Sahni - 7 years, 3 months ago

Log in to reply

Still, Kushagra, try to understand that we are finding only the number of zeros at the end of the number. How do we know whether there are any in between or not!

Satvik Golechha - 7 years, 3 months ago

Log in to reply

I agreed with you earlier also

Kushagra Sahni - 7 years, 3 months ago
Arya Haldar
Aug 22, 2014

I agree with Satvik, the answer is very easy- You just need have basic concept of greatest integer. [1994/5] +[1994/25]+[1994/125]+[1994/625]=398+79+15+3=398 (ans) where:[x] denotes the greatest integer of X, The logic behind it is- number of zeros formed comprises-2* 5 Since 2 is in excess, we need not worry about it, so we find number of 5 present in the equation. Since, every square multiple of 5 such as multiple of 25,125,625 has more 5^x we add them separately. We do not take the decimal part, that's why greatest integer has been introduced. Good day!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...