An algebra problem by Nischay Singh

Algebra Level 3

Find the value of the expression below:

log ( tan ( 1 ) ) × log ( tan ( 2 ) ) × log ( tan ( 3 ) ) × × log ( tan ( 8 8 ) ) × log ( tan ( 8 9 ) ) \log(\tan(1^\circ)) \times \log(\tan(2^\circ)) \times \log(\tan(3^\circ)) \times \ldots \times \log(\tan(88^\circ)) \times \log(\tan(89^\circ))


The answer is 0.

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2 solutions

In the series, we get log (tan ( 4 5 o ) (45^{o}) ) as a term.

We know that tan ( 4 5 o ) (45^{o}) = 1.

So we get log (1), and we know that log (1) = 0, thus the product series totals to zero.

Nischay Singh
Dec 10, 2017

In the product series the term "log(tan45)" makes the whole product = 0 (Since Tan45 = 1 and log1=0)

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