If − 2 < x < 2 and − 5 < y < 5 , what is the range of all possible values of y − x ?
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Nice approach. Most people try to subtract "vertically" and get 3 < y − x < 3 .
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i did not get your point according to my knowledge this solution is for − 2 ≤ x ≤ 2 and − 5 ≤ y ≤ 5 and in question their is no equality sign in equation
Min Val for x is -1 and min Val for y is -1. Do the math sherlock
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The variables need not be integers. For example, we could have x = 0 . 5 . Note also that − 5 < y < 5 so the min integer value of y us not -1.
In order to find the range, say we want to minimize y − x , then we actually want the minimum of y and the maximum of x . For example, if we set y = − 4 . 9 and x = 1 . 9 , we actually end up with y − x = − 6 . 8 .
min(y - x) = min(y) - max(x) = -5 - 2 = -7. max(y - x) = max(y) - min(x) = 5 - -2 = 7
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The greatest value of y − x is where y is maximized and x is minimized, so y − x < 5 − ( − 2 ) = 7 .
Similarly, the least value of y − x is where y is minimized and x is maximized, so y − x > − 5 − ( 2 ) = − 7 .
It's obvious that all of the values in-between can be achieved, so the range of possible values is − 7 < y − x < 7 .