Beyond the 12 Days of Christmas

Algebra Level 3

In “The Twelve Days of Christmas” song, the singer’s true love gives her 1 1 gift the first day, 2 + 1 2 + 1 gifts the second day, 3 + 2 + 1 3 + 2 + 1 gifts the third day, and so on.

Not to be outdone, the singer has a new suitor who decides to give her 1 2 1^2 gifts the first day, 2 2 2^2 gifts the second day, 3 2 3^2 gifts the third day, and so on.

Let T ( n ) T(n) be the total number of accumulated gifts given by the singer’s true love after n n days, and S ( n ) S(n) be the total number of accumulated gifts given by the singer’s new suitor after n n days.

Find lim n S ( n ) T ( n ) \displaystyle \lim_{n \to \infty} \frac{S(n)}{T(n)} .


The answer is 2.

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1 solution

Gabriel Chacón
Dec 23, 2018

We can answer the question without finding the expressions for T ( n ) T(n) and S ( n ) S(n) .

Let's consider what the singer receives the n n -th day:

  • From her true love: t n = 1 + 2 + + ( n 1 ) + n = n ( n + 1 ) 2 t_n=1+2+\ldots+(n-1)+n=\dfrac{n(n+1)}{2}^*

  • From the new suitor: s n = n 2 s_n=n^2

lim n s n t n = lim n n 2 n 2 + n 2 = lim n 2 1 1 + 1 n = 2 \displaystyle \lim_{n \to \infty}\dfrac{s_n}{t_n}=\lim_{n \to \infty}\dfrac{n^2}{\frac{n^2+n}{2}}=\lim_{n \to \infty}2\cdot \dfrac{1}{1+\frac{1}{n}}=2 , and this is also true for the quotient of the sums, as their terms grow indefinitely and make the initial deviation from this ratio fade away. lim n S ( n ) T ( n ) = 2 \displaystyle \lim_{n \to \infty}\dfrac{S(n)}{T(n)}=\boxed 2


* This follows from observing that 1 + n = 2 + ( n 1 ) = 3 + ( n 2 ) = 1+n=2+(n-1)=3+(n-2)=\ldots and that there are n / 2 n/2 of these couples.

Great solution!

David Vreken - 2 years, 5 months ago

Great problem... And solution!

My only comment is that n n isn't mentioned until the very last line.

Although perhaps intuitive, perhaps it should be defined and/or mentioned earlier in the problem?

Geoff Pilling - 2 years, 5 months ago

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You're right, when I wrote the problem I accidentally used x and n interchangeably. I edited the problem and changed all the x's to n's.

David Vreken - 2 years, 5 months ago

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Ah yes... much cleaner! :)

Geoff Pilling - 2 years, 5 months ago

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