big factorial !!

All zeros to right of factorial $2015^2$ come from digit $5$ and its multiples.
To find the number of zeros you need only to count the number of $5's, 25's, 125', and ... etc. in \ 2015^2$

$\left \lfloor \dfrac{2015^2}{5} \right \rfloor +\left \lfloor \dfrac{2015^2}{25} \right \rfloor+\left \lfloor \dfrac{2015^2}{125} \right \rfloor +\cdots =$

$812045 + 162409 + 32481 + 6496 + 1299 + 259 + 51 + 10 + 2 = 1015052$